The angular momentum of an electron moving in an orbit of hydrogen atom is . The energy in the same orbit is nearly [2023]

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Solution

Q.
The angular momentum of an electron moving in an orbit of hydrogen atom is $1.5 (\frac{h}{π})$ . The energy in the same orbit is nearly [2023]

1 $- 1.5$ eV

2 $- 1.6$ eV

3 $- 1.3$ eV

4 $- 1.4$ eV

Ans.
(1)

For angular momentum $(L) = 1.5 \frac{h}{π} = 3 (\frac{h}{2 π})$

Hence, $n = 3$

$E_{3} = \frac{- 13.6}{n^{2}} = \frac{- 13.6}{9} = - 1.51$ $eV$

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