The angular momentum for the electron in Bohr’s orbit is L. If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be [2023]

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Solution

Q.
The angular momentum for the electron in Bohr’s orbit is L. If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be [2023]

1 $\frac{L}{2}$

2 $zero$

3 $L$

4 $2 L$

Ans.
(3)

$L = m v r, r \propto n^{2}, v \propto \frac{1}{n}$
$∴$ $L \propto n$

Also, $L = \frac{n h}{2 π}$ ,

Bohr orbit is, $L_{1} = L = \frac{1 h}{2 π}$

$L_{2} = 2 [L] = 2 L$

$L_{2} = \frac{2 h}{2 π}$

So change = $L_{2} - L_{1} = 2 L - L = L$

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