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Solution


Q.

The amount of electricity in Coulomb required for the oxidation of 1 mol of H2O to O2 is ________ ×105C.              [2024]

Ans.

(2)

                   Oxidation of water to oxygen is represented by:

                   2H2O→O2+4H++4e-

                   By stoichiometry:

                   ne-4=nH2O2

                  ne-4=12

                  ne-=2 mol

                  Charge on 1 mol electrons have = 96500C

                  Charge on 2 mol electrons = 2 × 96500 C

                                                               =1.93×105 C≈2×105 C

                  Hence, 2×105 C electricity is required for oxidation of 1 mol of water.