Q.

The 4th term of GP is 500 and its common ratio is 1/m,mN. Let Sn denote the sum of the first n terms of this GP. If S6>S5+1 and S7<S6+12, then the number of possible values of m is _______ .        [2023]


Ans.

(12)

Let the first term be A

T4=500  ;  Am3=500

S6-S5>1T6>1Am5>1

500m2>1m2<500m<500

m22                     (m)

     S7-S6<12T7<12 Am6<12500m3<12

m3>1000m11

Thus, 11m22

   m can take 12 values.