Q.

The 4th term of GP is 500 and its common ratio is 1/m,m∈N. Let Sn denote the sum of the first n terms of this GP. If S6>S5+1 and S7<S6+12, then the number of possible values of m is _______ .        [2023]


Ans.

(12)

Let the first term be A

T4=500  ;  Am3=500

S6-S5>1⇒T6>1⇒Am5>1

⇒500m2>1⇒m2<500⇒m<500

⇒m≤22                     (∵m∈ℕ)

     S7-S6<12⇒T7<12⇒ Am6<12⇒500m3<12

⇒m3>1000⇒m≥11

Thus, 11≤m≤22

∴   m can take 12 values.