Suppose ∑r=02023 r2 Cr2023=2023×α×22022. Then the value of α is ___________ . [2023]
(1012)
∑r=02023r2 Cr2023=2023×α×22022
∑r=0nr2·Crn=n(n+1)·2n-2
Then, ∑r=02023r2·Cr2023=(2023)(2023+1)·22023-2
=2023×2024×22021=2023×α×22022
∴ 2α=2024 ⇒ α=1012