Sum of bond order of CO and is

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Solution

Q.
Sum of bond order of CO and ${NO}^{+}$ is _________ . [2024]

Ans.
(6)

$Electronic configuration of {NO}^{+} is written as :$

$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2}$

$Bond order of {NO}^{+} = \frac{1}{2} \times (N_{b} - N_{a}) = \frac{1}{2} \times (10 - 4) = 3$

$Actual electronic configuration of CO is :$

$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < σ 2 p_{z}^{2} < σ^{} 2 s^{2}$

$Bond order of CO = \frac{1}{2} \times (N_{b} - N_{a}) = \frac{1}{2} \times (10 - 4) = 3$

$Sum of bond orders of CO and {NO}^{+} = 6$

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