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Solution


Q.

Given below are two statements:                                                  [2024]

Statement I: Aniline reacts with con. H2SO4, followed by heating at 453-473 K, gives p-aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.

Statement II: In Friedel-Craft's alkylation and acylation reactions, aniline forms salt with the AlCl3 catalyst. Due to this, nitrogen of aniline acquires a positive charge and acts as a deactivating group.

In the light of the above statements, choose the correct answer from the options given below:
1 Both statement I and statement II are true  
2 Both statement I and statement II are false  
3 Statement I is true but statement II is false  
4 Statement I is false but statement II is true  

Ans.

(1)

Statement (I)

In sulphanilic acid, nitrogen and sulphur both are present. So, in sodium fusion extract of sulphanilic acid, sodium thiocyanate is formed.

Na+C+N+S→ΔNaSCN

                                Sodium thiocyanate

Sodium thiocyanate gives blood-red colour with Fe3+ in Lassaigne’s test.

Fe3++SCN-→[Fe(SCN)]2+

                                 Blood red

Statement (II) : Aniline does not give Friedel-Craft’s alkylation and acylation reaction because aniline forms salt with AlCl3 (Lewis acid catalyst in the reaction). Due to this, nitrogen of aniline acquires a positive charge and hence acts as a strong deactivating group for further reaction.