Spin paired Complex, Spin free Complex, are respectively known as:

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Solution

Q.
${[Co {({NH}_{3})}_{6}]}^{3 +}$ and ${[{CoF}_{6}]}^{3 -}$ are respectively known as: [2024]

1 Inner orbital Complex, Spin paired Complex

2 Spin paired Complex, Spin free Complex

3 Spin free Complex, Spin paired Complex

4 Outer orbital Complex, Inner orbital Complex

Ans.
(2)

${[Co {({NH}_{3})}_{6}]}^{3 +}$

Oxidation number of Co = +3

${Co}^{3 +} = {}_{18}{[Ar] 3 d^{6}}$

${NH}_{3}$ is a strong field ligand. It pairs up d electrons. After pairing d electrons, two 3d orbitals are vacant. ${C o}^{3 +}$ undergoes $d^{2} s p^{3}$ hybridisation by using two 3d orbitals. Six $e^{-}$ pairs from six ${NH}_{3}$ are accommodated in these six $d^{2} s p^{3}$ orbitals.

As inner shell d orbitals (3d) are used for hybridisation, it is an inner orbital complex. Since it has a low number of unpaired electrons, it is a spin-paired complex.

${[{CoF}_{6}]}^{3 -}$

Oxidation number of Co = +3

${Co}^{3 +} = {}_{18}{[Ar] 3 d^{6}}$

$F^{-}$ is a weak field ligand. It cannot pair up d electrons. Thus, 4d orbitals are used for $s p^{3} d^{2}$ hybridisation. Six $e^{-}$ pairs from six $F^{-}$ are accommodated in these six $s p^{3} d^{2}$ orbitals.

Since outer orbital (4d) is used in hybridisation, it is an outer orbital complex. Since it has a high number of unpaired electrons, it is a spin-free complex.

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