Q.

Some amount of dichloromethane (CH2Cl2) is added to 671.141 mL of chloroform (CHCl3) to prepare 2.6×10-3 M solution of CH2Cl2 (DCM). The concentration of DCM is ______ ppm (by mass). Given: atomic mass: C = 12, H = 1, Cl = 35.5; density of CHCl3 = 1.49 g cm-3.                 [2023]


Ans.

(148)

Molarity=W×1000Mw×V

2.6×10-3=W×100085×671.141

W=2.6×10-3×85×671.1411000=0.148 g

Concn. of DCM (in ppm)=0.1481.49×671.141×106=148 ppm