Q.

Solid sphere A is rotating about an axis PQ. If the radius of the sphere is 5 cm, then its radius of gyration about PQ will be x cm. The value of x is ________.    [2023]


Ans.

(110)

Icm=25MR2

IPQ=Icm+md2

IPQ=25mR2+m(10 cm)2

For radius of gyration, IPQ=mk2

k2=25R2+(10 cm)2

          =25(5)2+100=10+100=110

k=110cm

x=110