Reduction potential of ions are given below, The correct order of their oxidising power is:

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Q.
Reduction potential of ions are given below:

${ClO}_{4}^{-}$ ${IO}_{4}^{-}$ ${BrO}_{4}^{-}$

$E^{°} = 1.19 V$ $E^{°} = 1.65 V$ $E^{°} = 1.74 V$

The correct order of their oxidising power is: [2024]

1 ${ClO}_{4}^{-} > {IO}_{4}^{-} > {BrO}_{4}^{-}$

2 ${BrO}_{4}^{-} > {IO}_{4}^{-} > {ClO}_{4}^{-}$

3 ${BrO}_{4}^{-} > {ClO}_{4}^{-} > {IO}_{4}^{-}$

4 ${IO}_{4}^{-} > {BrO}_{4}^{-} > {ClO}_{4}^{-}$

Ans.
(2)

Oxidising power $\propto$ reduction potential.

So more is reduction potential of a specie, more is its ability to oxidize the other substance.

$\to_{Decreasing oxidising power}^{{BrO}_{4}^{-} (E ° = 1.74 V) > {IO}_{4}^{-} (E ° = 1.65 V) > {ClO}_{4}^{-} (E ° = 1.19 V)}$

Solution

Q.
Reduction potential of ions are given below:

${ClO}_{4}^{-}$ ${IO}_{4}^{-}$ ${BrO}_{4}^{-}$

$E^{°} = 1.19 V$ $E^{°} = 1.65 V$ $E^{°} = 1.74 V$

The correct order of their oxidising power is: [2024]

1 ${ClO}_{4}^{-} > {IO}_{4}^{-} > {BrO}_{4}^{-}$

2 ${BrO}_{4}^{-} > {IO}_{4}^{-} > {ClO}_{4}^{-}$

3 ${BrO}_{4}^{-} > {ClO}_{4}^{-} > {IO}_{4}^{-}$

4 ${IO}_{4}^{-} > {BrO}_{4}^{-} > {ClO}_{4}^{-}$

Ans.
(2)

Oxidising power $\propto$ reduction potential.

So more is reduction potential of a specie, more is its ability to oxidize the other substance.

$\to_{Decreasing oxidising power}^{{BrO}_{4}^{-} (E ° = 1.74 V) > {IO}_{4}^{-} (E ° = 1.65 V) > {ClO}_{4}^{-} (E ° = 1.19 V)}$

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Solution

Q. Reduction potential of ions are given below: ClO4- IO4- BrO4- E°=1.19V E°=1.65V E°=1.74V The correct order of their oxidising power is: [2024]

1 ClO4->IO4->BrO4-

2 BrO4->IO4->ClO4-

3 BrO4->ClO4->IO4-

4 IO4->BrO4->ClO4-

Ans. (2) Oxidising power ∝ reduction potential. So more is reduction potential of a specie, more is its ability to oxidize the other substance. →Decreasing oxidising powerBrO4-(E°=1.74 V)>IO4-(E°=1.65 V)>ClO4-(E°=1.19 V)

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Q.
Reduction potential of ions are given below:

${ClO}_{4}^{-}$ ${IO}_{4}^{-}$ ${BrO}_{4}^{-}$

$E^{°} = 1.19 V$ $E^{°} = 1.65 V$ $E^{°} = 1.74 V$

The correct order of their oxidising power is: [2024]

1 ${ClO}_{4}^{-} > {IO}_{4}^{-} > {BrO}_{4}^{-}$

2 ${BrO}_{4}^{-} > {IO}_{4}^{-} > {ClO}_{4}^{-}$

3 ${BrO}_{4}^{-} > {ClO}_{4}^{-} > {IO}_{4}^{-}$

4 ${IO}_{4}^{-} > {BrO}_{4}^{-} > {ClO}_{4}^{-}$

Ans.
(2)

Oxidising power $\propto$ reduction potential.

So more is reduction potential of a specie, more is its ability to oxidize the other substance.

$\to_{Decreasing oxidising power}^{{BrO}_{4}^{-} (E ° = 1.74 V) > {IO}_{4}^{-} (E ° = 1.65 V) > {ClO}_{4}^{-} (E ° = 1.19 V)}$