Pick out the correct statement with respect to [ Mn ( CN ) 6 ] 3

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Q.
Pick out the correct statement with respect to ${[Mn {(CN)}_{6}]}^{3 -}$ . [2017]

1 It is $s p^{3} d^{2}$ hybridised and tetrahedral.

2 It is $d^{2} s p^{3}$ hybridised and octahedral.

3 It is $d s p^{2}$ hybridised and square planar.

4 It is $s p^{3} d^{2}$ hybridised and octahedral.

Ans.
(2)

${[Mn {(CN)}_{6}]}^{3 -}$ : Let oxidation state of Mn be $x$ .

$x + 6 \times (- 1) = - 3 \Rightarrow x = + 3$

Electronic configuration of Mn: $[Ar] 3 d^{5} 4 s^{2}$

Electronic configuration of ${Mn}^{3 +}$ : $[Ar] 3 d^{4}$

${CN}^{-}$ is a strong field ligand, it causes pairing of electrons in the $3 d$ orbital.

Thus, ${[Mn {(CN)}_{6}]}^{3 -}$ has $d^{2} s p^{3}$ hybridisation and has octahedral geometry.

Solution

Q.
Pick out the correct statement with respect to ${[Mn {(CN)}_{6}]}^{3 -}$ . [2017]

1 It is $s p^{3} d^{2}$ hybridised and tetrahedral.

2 It is $d^{2} s p^{3}$ hybridised and octahedral.

3 It is $d s p^{2}$ hybridised and square planar.

4 It is $s p^{3} d^{2}$ hybridised and octahedral.

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Solution

Q. Pick out the correct statement with respect to [Mn(CN)6]3-. [2017]

1 It is sp3d2 hybridised and tetrahedral.

2 It is d2sp3 hybridised and octahedral.

3 It is dsp2 hybridised and square planar.

4 It is sp3d2 hybridised and octahedral.

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Q.
Pick out the correct statement with respect to ${[Mn {(CN)}_{6}]}^{3 -}$ . [2017]

1 It is $s p^{3} d^{2}$ hybridised and tetrahedral.

2 It is $d^{2} s p^{3}$ hybridised and octahedral.

3 It is $d s p^{2}$ hybridised and square planar.

4 It is $s p^{3} d^{2}$ hybridised and octahedral.