Q.

Photons with energy 5 eV are incident on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A, if the stopping potential of A relative to C is              [2016]

1 +3 V  
2 +4 V  
3 –1 V  
4 –3 V  

Ans.

(4)

According to Einstein's photoelectric equation, maximum kinetic energy of photoelectrons,

         KEmax=Eν-ϕ

or      2=5-ϕ    ϕ=3eV

When  Eν=6 eV then, KEmax=6-3=3 eV

or   e(Vcathode-Vanode)=3 eV

or   Vcathode-Vanode=3V=-Vstopping

   Vstopping=-3 V