On complete combustion, 0.492 g of an organic compound gave 0.792 g of . The % of carbon in the organic compound is _______. (Nearest Integer) [2023]

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Solution

Q.
On complete combustion, 0.492 g of an organic compound gave 0.792 g of $C O_{2}$ . The % of carbon in the organic compound is _______. (Nearest Integer) [2023]

Ans.
(44)

$44 gm of {CO}_{2} contains 12 g carbon$

$0.792 gm of {CO}_{2} contains \frac{0.792 \times 12}{44} g of carbon$

$% of carbon = \frac{0.216}{0.492} \times 100 = 43.9 % \approx 44 %$

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