On charging the lead storage battery, the oxidation state of lead changes from to at the anode and from to at the cathode. The values of are respectively: [2025]

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Solution

Q.
On charging the lead storage battery, the oxidation state of lead changes from $x_{1}$ to $y_{1}$ at the anode and from $x_{2}$ to $y_{2}$ at the cathode. The values of $x_{1}, y_{1}, x_{2}, y_{2}$ are respectively: [2025]

1 +4, +2, 0, +2

2 +2, 0, +2, +4

3 0, +2, +4, +2

4 +2, 0, 0, +4

Ans.
(2)

The reactions in lead storage battery, when the battery is in use are given below:

$Anode reaction:$

$Pb (s) + {SO}_{4}^{2 -} (aq) \to {PbSO}_{4} (s) + 2 e^{-}$

$Cathode reaction:$

${PbO}_{2} (s) + {SO}_{4}^{2 -} (aq) + 4 H^{+} (aq) + 2 e^{-} \to {PbSO}_{4} (s) + 2 H_{2} O (l)$

On charging the battery the reaction is reversed and $\overset{+ 2}{Pb} {SO}_{4} (s)$ on anode and cathode is converted into $\overset{0}{Pb}$ and $\overset{+ 4}{Pb} O_{2} (s)$ , respectively.

$So x_{1} = 2, y_{1} = 0, x_{2} = 2, y_{2} = 4$

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