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Solution


Q.

2.8×10-3 mol of CO2 is left after removing 1021molecules from its ‘x’ mg sample. The mass of CO2 taken initially is

Given: NA=6.02×1023 mol-1                                            [2025]
1 48.2 mg  
2 98.3 mg  
3 150.4 mg  
4 196.2 mg  

Ans.

(4)

1021 molecules=10216.02×1023 mol =1.66×10-3 mol

Initial moles = mole left + mole removed

Initial moles =2.8×10-3 mol+1.66×10-3 mol

                    =4.46×10-3 mol

Initial mass=Initial moles×molar mass

                      =4.46×10-3 mol×44 g mol-1

                      =196.24×10-3 g=196.24 mg