Match List I with List II. Electrochemistry NEET Previous Year Questions with Answer [2024]

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Q.
Match List I with List II. [2024]

List I List II

(Conversion) (Number of Faraday required)

A. 1 mol of $H_{2} O$ to $O_{2}$ I. 3 F

B. 1 mol of ${MnO}_{4}^{-}$ to ${Mn}^{2 +}$ II. 2 F

C. 1.5 mol of Ca from molten ${CaCl}_{2}$ III. 1 F

D. 1 mol of FeO to ${Fe}_{2} O_{3}$ IV. 5 F

Choose the correct answer from the options given below:

1 A-II, B-IV, C-I, D-III

2 A-III, B-IV, C-I, D-II

3 A-II, B-III, C-I, D-IV

4 A-III, B-IV, C-II, D-I

Ans.
(1)

$H_{2} O \to 2 H^{+} + \frac{1}{2} O_{2} + 2 e^{-}$

$∴$ $No. of Faradays required for one mol = 2 F (A - II)$

${MnO}_{4}^{-} + 5 e^{-} \to {Mn}^{2 +}$

$∴$ $No. of Faradays required for one mol = 5 F (B - IV)$

${Ca}^{2 +} + 2 e^{-} \to Ca$

$∴$ $No. of Faradays required for 1.5 mol = 1.5 \times 2 = 3 F (C - I)$

${Fe}^{2 +} \to {Fe}^{3 +} + e^{-}$

$No. of Faradays required for one mol = 1 F (D - III)$

Solution

1 A-II, B-IV, C-I, D-III

2 A-III, B-IV, C-I, D-II

3 A-II, B-III, C-I, D-IV

4 A-III, B-IV, C-II, D-I

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	List I		List II
	(Conversion)		(Number of Faraday required)
A.	1 mol of $H_{2} O$ to $O_{2}$	I.	3 F
B.	1 mol of ${MnO}_{4}^{-}$ to ${Mn}^{2 +}$	II.	2 F
C.	1.5 mol of Ca from molten ${CaCl}_{2}$	III.	1 F
D.	1 mol of FeO to ${Fe}_{2} O_{3}$	IV.	5 F

Solution

Q. Match List I with List II. [2024] List I List II (Conversion) (Number of Faraday required) A. 1 mol of H2O to O2 I. 3 F B. 1 mol of MnO4- to Mn2+ II. 2 F C. 1.5 mol of Ca from molten CaCl2 III. 1 F D. 1 mol of FeO to Fe2O3 IV. 5 F Choose the correct answer from the options given below:

1 A-II, B-IV, C-I, D-III

2 A-III, B-IV, C-I, D-II

3 A-II, B-III, C-I, D-IV

4 A-III, B-IV, C-II, D-I

Ans. (1) H2O→2H++12O2+2e- ∴ No. of Faradays required for one mol=2F(A-II) MnO4-+5e-→Mn2+ ∴ No. of Faradays required for one mol=5F(B-IV) Ca2++2e-→Ca ∴ No. of Faradays required for 1.5 mol=1.5×2=3F(C-I) Fe2+→Fe3++e- No. of Faradays required for one mol=1F(D-III)

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