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Solution


Q.

Match List-I with List-II

  List I   List II
A. [Fe(CN)6]3- i. 5.92 BM
B. [Fe(H2O)6]3+ ii. 0 BM
C. [Fe(CN)6]4- iii. 4.90 BM
D. [Fe(H2O)6]2+ iv. 1.73 BM

 

Choose the correct answer from the options given below:                       [2021]
1 (A) – (iv), (B) – (i), (C) – (ii), (D) – (iii)  
2 (A) – (iv), (B) – (ii), (C) – (i), (D) – (iii)  
3 (A) – (ii), (B) – (iv), (C) – (iii), (D) – (i)  
4 (A) – (i), (B) – (iii), (C) – (iv), (D) – (ii)  

Ans.

(1)

[Fe(CN)6]3-

Spin only magnetic moment = n(n+2)

where n = number of unpaired electrons.

Hence, n=1

μ=1(1+2)=3=1.73 B.M.

n=5,   μ=5(5+2)=35=5.92 B.M.

n=0,   μ=0=0 B.M.

n=4,   μ=4(4+2)=24=4.90 B.M.