Match List I with List II. [2023] List I List II Complex Crystal field splitting energy ( o ) A. [ Ti ( H 2 O ) 6 ] 2 + I. - 1.2 B. [ V ( H 2 O ) 6 ] 2 + II. - 0.6 C. [ Mn ( H 2 O ) 6 ] 3 + III. 0 D. [ Fe ( H 2 O ) 6 ] 3

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Solution

Q.
Match List I with List II. [2023]

List I List II

Complex Crystal field splitting energy $(Δ_{o})$

A. ${[Ti {(H_{2} O)}_{6}]}^{2 +}$ I. - 1.2

B. ${[V {(H_{2} O)}_{6}]}^{2 +}$ II. - 0.6

C. ${[Mn {(H_{2} O)}_{6}]}^{3 +}$ III. 0

D. ${[Fe {(H_{2} O)}_{6}]}^{3 +}$ IV. - 0.8

Choose the correct answer from the options given below:

1 A–IV, B–I, C–III, D–II

2 A–II, B–IV, C–III, D–I

3 A–II, B–IV, C–I, D–III

4 A–IV, B–I, C–II, D–III

Ans.
(4)

$(A) {[Ti {(H_{2} O)}_{6}]}^{2 +}; OS of Ti = + 2$

${Ti}^{2 +} = 3 d^{2} (t_{2 g}^{1, 1, 0}, e_{g}^{0, 0})$

   $C.F.S.E = - 0.8 Δ_{o} (IV)$

$(B) {[V {(H_{2} O)}_{6}]}^{2 +}; OS of V = + 2$

$V^{2 +} = 3 d^{3} (t_{2 g}^{1, 1, 1}, e_{g}^{0, 0})$

   $C.F.S.E = - 1.2 Δ_{o} (I)$

$(C) {[Mn {(H_{2} O)}_{6}]}^{3 +}; OS of Mn = + 3$

${Mn}^{3 +} = 3 d^{4} (t_{2 g}^{1, 1, 1}, e_{g}^{1, 0})$

$C.F.S.E = (- 1.2 + 0.6) Δ_{o} = - 0.6 Δ_{o} (II)$

$(D) {[Fe {(H_{2} O)}_{6}]}^{3 +}; OS of Fe = + 3$

   $\Rightarrow 3 d^{5} (t_{2 g}^{1, 1, 1}, e_{g}^{1, 1})$

$C.F.S.E = 0 (III)$

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