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Solution


Q.

Mass of magnesium required to produce 220 mL of hydrogen gas at STP on reaction with excess of dil. HCl is

Given: Molar mass of Mg is 24 g mol-1.                                      [2025]
1 235.7 g  
2 0.24 mg  
3 236 mg  
4 2.444 g  

Ans.

(3)

Moles of hydrogen gas (nH2)

=Volume of hydrogen at STP in mL22400=22022400 mol

Mg+2HCl→MgCl2+H2

As per reaction stoichiometry, moles of Mg (nMg) = nH2

=22022400 mol

Mass of Mg (WMg)

=nMg×MMg

=22022400×24 g =0.2357 g=235.7 mg