limx→∞(2x2–3x+5)(3x–1)x2(3x2+5x+4)(3x+2)x is equal to : [2025]
(2)
limx→∞(2–3x+5x2)(1–13x)x/2(3+5x+4x2)(1+23x)x/2
=limx→∞23·ex2(1–13x–1)ex2(1+23x–1)
=23·e–16e13=23e.