limx→0cosec x(2 cos2x+3 cos x–cos2x+sin x+4) is : [2025]
(1)
limx→0cosec x(2 cos2x+3 cos x–cos2x+sin x+4)
=limx→01sin x[2 cos2x+3 cos x–cos2x–sin x–42 cos2x+3 cos x+cos2x+sin x+4]
=limx→01sin x[cos2x+3 cos x–sin x–42 cos2x+3 cos x+cos2x+sin x+4]
=limx→0[(cosx+4)(cosx–1)–sin xsin x]×limx→0[12cos2x+3cosx+cos2x+sinx+4]
=125limx→0[(cosx+4)(–2sin2x2)–2 sinx2cosx2)2 sinx2cosx2]
=125limx→0[(–sinx2)(cos x+4)–cosx2cosx2]
=125[–1]=–125.