Let us consider a reversible reaction at temperature, . In this reaction, both and were observed to have positive values. If the equilibrium temperature is , then the reaction becomes spontaneous at : [2025]

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Solution

Q.
Let us consider a reversible reaction at temperature, $T$ . In this reaction, both $Δ H$ and $Δ S$ were observed to have positive values. If the equilibrium temperature is $T_{e}$ , then the reaction becomes spontaneous at : [2025]

1 $T = T_{e}$

2 $T_{e} > T$

3 $T > T_{e}$

4 $T_{e} = 5 T$

Ans.
(3)

When reaction is at equilibrium, then:

$Δ G = 0$

$Δ H - T_{e} Δ S = 0$

$T_{e} = \frac{Δ H}{Δ S}$

For reaction to be spontaneous:

$Δ G < 0$

$Δ H - T Δ S < 0$

$T Δ S > Δ H$

$T > \frac{Δ H}{Δ S}$

$T > T_{e}$

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