Q.

Let the three sides of a triangle ABC be given by the vectors 2i^j^+k^i^3j^5k^ and 3i^4j^4k^. Let G be the centroid of the triangle ABC. Then 6(|AG|2+|BG|2+|CG|2) is equal to __________.          [2025]


Ans.

(164)

We have in ABCAB+CA=BC

Let PV of A be 0 then AB=BA

 P.V. of B=2i^j^+k^

CA=AC

P.V. of C=i^+3j^+5k^

Now, P.V. of G=A+B+C3=13(i^+2j^+6k^)

Then AG=13(i^+2j^+6k^)

 |AG|2=419

 BG=(132)i^+(23+1)j^+(21)k^

 |BG|2=599

 CG=(13+1)i^+(233)j^+(25)k^

 |CG|2=1469

  6(|AG|2+|BG|2+|CG|2)=6(419+599+1469)=164.