Q.

Let the position vectors of the points A, B, C and D be  5i^+5j^+2λk^, i^+2j^+3k^,-2i^+λj^+4k^ and -i^+5j^+6k^. Let the set S={λ∈ℝ: the points A, B, C and D are coplanar}. Then ∑λ∈S(λ+2)2 is equal to           [2023]

1 372  
2 25  
3 13  
4 41  

Ans.

(4)

We have, AB→=-4i^-3j^+(3-2λ)k^

AC→=-7i^+(λ-5)j^+(4-2λ)k^

AD→=-6i^+(6-2λ)k^

Since A, B, C and D are coplanar

∴|-4-33-2λ-7λ-54-2λ-606-2λ|=0

⇒-4[(λ-5)(6-2λ)-0] +3[-7(6-2λ)+6(4-2λ)]+(3-2λ)[0+6(λ-5)]=0

⇒-4(16λ-2λ2-30)+3(2λ-18)+(3-2λ)(6λ-30)=0

⇒λ2-5λ+6=0⇒λ=2 or λ=3        ∴S={2,3}

So, ∑λ∈S(λ+2)2=42+52=41