Q.

Let the point A divide the line segment joining the points P(–1, –1, 2) and Q(5, 5, 10) internally in the ratio r : 1 (r > 0). If O is the origin and (OQ→·OA→)–15|OP→×OA→|2=10, then the value of r is :          [2025]

1 7  
2 7  
3 3  
4 14  

Ans.

(1)

The point A divides line segment PQ internally in the ratio r : 1

∴  A≡(5r–1r+1,5r–1r+1,10r+2r+1)

Now, OQ→·OA→=10r+1(15r+1)

and |OP→×OA→|2=r2(r+1)2(800)

(OQ→·OA→)–|OP→×OA→|25=10

⇒ 10r+1(15r+1)–15r2(800)(r+1)2=10

⇒ 2r2–14r=0 ⇒ r=7, r≠0 .