Q.

Let the point A divide the line segment joining the points P(–1, –1, 2) and Q(5, 5, 10) internally in the ratio r : 1 (r > 0). If O is the origin and (OQ·OA)15|OP×OA|2=10, then the value of r is :          [2025]

1 7  
2 7  
3 3  
4 14  

Ans.

(1)

The point A divides line segment PQ internally in the ratio r : 1

  A(5r1r+1,5r1r+1,10r+2r+1)

Now, OQ·OA=10r+1(15r+1)

and |OP×OA|2=r2(r+1)2(800)

(OQ·OA)|OP×OA|25=10

 10r+1(15r+1)15r2(800)(r+1)2=10

 2r214r=0  r=7, r0 .