Let the circle x2+y2=4 intersect x-axis at the points A(a,0), a>0 and B(b,0). Let P(2cosα, 2sinα) 0<α<π2 and Q(2cosβ, 2sinβ) be two points such that (α-β)=π2. Then the point of intersection of AQ and BP lies on : [2026]
(2)