Let the area of the region {(x,y):2y≤x2+3, y+|x|≤3, y≥|x–1|} be A. Then 6A is equal to : [2025]
(1)
Required area, A = Rectangle ABDE – Area of region EDC
⇒ A=4–2∫01((3–x)–(x2+32))dx
⇒ A=4–2{3x–x22–x36–32x}01
⇒ A=4–2{3–12–16–32}=73
So, 6A = 14.