Let R = {a, b, c, d, e} and S = {1, 2, 3, 4}. Total number of onto functions f:R→S such that f(a)≠1, is equal to ________ . [2023]
(180)
Total onto functions
=45-C14×35+C24×25-C34×15=240
Now, when f(a)=1
⌊4+⌊4⌊2⌊2×⌊3=24+36=60
So, required number of onto functions =240-60=180