Q.

Let O be the vertex of the parabola x2 = 4y and Q be any point on it. Let the locus of the point P, which divides the line segment OQ internally in the ratio 2 : 3 be the conic C. Then the equation of the chord of C, which is bisected at the point (1, 2), is:   [2026]

1 4x-5y+6=0  
2 x-2y+3=0  
3 5x-4y+3=0  
4 5x-y-3=0  

Ans.

(3)

h=4t5

k=2t25=25(5h4)2

8k=5h2

5x2=8y

T=S1

5(xx1)-4(y+y1)=5x12-8y1

5x-4(y+2)=5-8·2

5x-4y+3=0