Q.

Let O be the origin and the position vector of the point P be -i^-2j^+3k^. If the position vectors of the points A, B and C are -2i^+j^-3k^, 2i^+4j^-2k^ and -4i^+2j^-k^ respectively, then the projection of the vector OP on a vector perpendicular to the vectors AB and AC is               [2023]

1 83  
2 73  
3 3  
4 103  

Ans.

(3)

We know that

AB=OB-OA=(2i^+4j^-2k^)-(-2i^+j^-3k^)=4i^+3j^+k^

AC=OC-OA=(-4i^+2j^-k^)-(-2i^+j^-3k^)=-2i^+j^+2k^

Now,  AB×AC=|i^j^k^431-212|=5i^-10j^+10k^

Also,  OP=-i^-2j^+3k^

Projection of OP on the vector perpendicular to the vectors AB and AC is given by

 OP·(AB×AC)|AB×AC|=(-i^-2j^+3k^)(5i^-10j^+10k^)52+(-10)2+(10)2

=-5+20+30225=4515=3