Let f(x)=x5+2ex/4 for all x∈R. Consider a function g(x) such that (gof) (x)=x for all x∈R. Then the value of 8g'(2) is [2024]
(2)
We have, (gof)(x)=x⇒g(f(x))=x
Differentiating w.r.t. x, we get
g'(f(x))·f'(x)=1⇒g'(f(x))=1f'(x)
Now, f(x)=x5+2ex/4⇒f'(x)=5x4+12ex/4
∴ f'(0)=12, f(0)=2⇒g'(2)=2
Hence, 8g'(2)=16