Q.

Let f(x) = logex and g(x)=x42x3+3x22x+22x22x+1. Then the domain of fog is          [2025]

1 (0,)  
2 [0,)  
3 [1,)  
4 R  

Ans.

(4)

Given, g(x)=x42x3+3x22x+22x22x+1

Here, DgR          [  2x22x+1>0]

Also, f(x)=logex  Df(0,)             Dfog g(x)>0

 x42x3+3x22x+22x22x+1>0  x42x3+3x22x+2>0

The above expression is always positive for any value of x.

   Domain of fog  R.