Q.

Let f:R→R be a thrice differentiable function such that f(0)=0, f(1)=1, f(2)=-1, f(3)=2 and f(4)=-2. Then, the minimum number of zeros of (3f'f''+ff''')(x) is _______ .         [2024]


Ans.

(5)

∵ f:R→R and f(0)=0, f(1)=1, f(2)=-1, f(3)=2 and f(4)=-2, then

∴ f(x) has at least 4 real roots.

Then f'(x) has atleast 3 real roots and f''(x) has atleast 2 real roots.

ddx(f3·f'')=3f2·f'·f''+f3·f'''=f2(3f'·f''+f·f''').

Hence, f3.f'' has at least 6 roots.

Then its differentiation has at least 5 distinct roots.