Q.

Let f be a real valued continuous function defined on the positive real axis such that g(x)=0xtf(t)dt. If g(x3)=x6+x7, then value of r=115f(r3) is :          [2025]

1 270  
2 340  
3 320  
4 310  

Ans.

(4)

We have, g(x)=0xtf(t)dt

g(x)=x2+x7/3  g'(x)=2x+73x4/3

As, f(x)=g'(x)x=2+73x1/3  f(r3)=2+7r3

  r=115(2+73r)=30+73[1+2+...+15]=310