Let be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and be the similar ratio of a diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio is

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Solution

Q.
Let $γ_{1}$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $γ_{2}$ be the similar ratio of a diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio $\frac{γ_{1}}{γ_{2}}$ is [2023]

1 $\frac{21}{25}$

2 $\frac{25}{21}$

3 $\frac{35}{27}$

4 $\frac{27}{35}$

Ans.
(2)

$For monoatomic gas, γ_{1} = \frac{5}{3}$

$For diatomic gas at low temperatures, γ_{2} = \frac{7}{5}$

$∴$ $\frac{γ_{1}}{γ_{2}} = \frac{\frac{5}{3}}{\frac{7}{5}} = \frac{25}{21}$

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