Let (α, β, γ) be the foot of the perpendicular from the point (1, 2, 3) on the line x+35=y–12=z+43. Then 19(α+β+γ) is equal to [2024]
(3)
Let x+35=y–12=z+43=λ
⇒ (α, β, γ)=(5λ–3,2λ+1,3λ–4)
Let B(α, β, γ) be the foot of perpendicular from A on the given line
Now, 5i^+2j^+3k^ is the direction vector of given line.
⇒ AB→·(5i^+2j^+3k^)=0
⇒ (5λ–4)5+(2λ–1)2+(3λ–7)3=0
⇒ 25λ+4λ+9λ=20+2+21
⇒ 38λ=43 ⇒ λ=4338
∴ 19(α+β+γ)=19(5λ–3+2λ+1+3λ–4)=19(10λ–6)
=19(10×4338–6)=215–114=101.