Q.

Let OA=a, OB=12a+4b and OC=b, where O is the origin. If S is the parallelogram with adjacent sides OA and OC, then area of the quadrilateral OABCarea of S is equal to __________.          [2024]

1 8  
2 10  
3 7  
4 6  

Ans.

(1)

We have,

Area of parallelogram, S=|OA×OC|=|a×b|          ... (i)

Area of quad. OABC = Area of OAB + Area of OBC

=12|OA×OB|+12|OB×OC|

=12|a×(12a+4b)|+12|(12a+4b)×b|

=12×(4|a×b|+12|a×b|)=8|a×b|

  Area of quad. OABCArea of parallelogram=8|a×b||a×b|=8.