Q.

Let a and b be two unit vectors such that the angle between them is π3. If λa+2b and 3aλb are perpendicular to each other, then the number of values of λ in [–1, 3] is :          [2025]

1 1  
2 0  
3 2  
4 3  

Ans.

(2)

a·b=|a||b|cosπ3=12          [ |a|=|b|=1]

Now, (λa+2b)·(3aλb)=0

 3λa·aλ2a·b+6b·a2λb·b=0

 3λλ22+32λ=0          [ |a|=|b|=1 and a·b=12]

 λ22λ6=0  λ=1±7[1,3]

 Number of values of λ = 0