Q.

Let a→ and b→ be two unit vectors such that the angle between them is π3. If λa→+2b→ and 3a→–λb→ are perpendicular to each other, then the number of values of λ in [–1, 3] is :          [2025]

1 1  
2 0  
3 2  
4 3  

Ans.

(2)

a→·b→=|a→||b→|cosπ3=12          [∵ |a→|=|b→|=1]

Now, (λa→+2b→)·(3a→–λb→)=0

⇒ 3λa→·a→–λ2a→·b→+6b→·a→–2λb→·b→=0

⇒ 3λ–λ22+3–2λ=0          [∵ |a→|=|b→|=1 and a→·b→=12]

⇒ λ2–2λ–6=0 ⇒ λ=1±7∉[–1,3]

⇒ Number of values of λ = 0