Q.

Let a→=3i^+j^-2k^, b→=4i^+j^+7k^ and c→=i^–3j^+4k^ be three vectors. If a vectors p→ satisfies p→×b→=c→×b→ and p→·a→=0, then p→·(i^–j^–k^) is equal to          [2024]

1 28  
2 32  
3 36  
4 24  

Ans.

(2)

Given, a→=3i^+j^–2k^, b→=4i^+j^+7k^ and c→=i^–3j^+4k^

Also, p→×b→=c→×b→

(p→–c→)×b→=0  ⇒  b→||p→–c→  ⇒  (p→–c→)=λb→

let λb→+c→=p→

⇒  p→=i^(4λ+1)+j^(λ–3)+k^(7λ+4)  ⇒  p→·a→=0

⇒  (4λ+1)3+(λ–3)(1)+(7λ+4)(–2)=0

⇒  12λ+3+λ–3–14λ–8  ⇒  λ=–8

∴  p→=–31i^–11j^–52k^

   p→·(i^–j^–k^)=–31+11+52

   p→·(i^–j^–k^)=32.