Let A={z∈C:|z–2–i|=3}, B={z∈C:Re(z–iz)=2} and S=A∩B. Then ∑z∈S|z|2 is equal to __________. [2025]
(22)
Let z = x + iy.
We have, A : |z – 2 – i| = 3
⇒ |(x–2)+i(y–1)|=3 ⇒ (x–2)2+(y–1)2=9 ... (i)
Also, B : Re(z – iz) = 2
Re((x+y)+i(y–x))=2 ⇒ x+y=2 ... (ii)
From (i) and (ii), we get x=3±172, y=1∓172
∴ ∑z∈S|z|2=14[2×26+2×18]=22.