Let A={(x,y)∈R×R:|x+y|≥3} and B={(x,y)∈R×R:|x|+|y|≤3}
If C={(x,y)∈A∩B:x=0 or y=0}, then ∑(x,y)∈C|x+y| is: [2025]
(2)
We have, A={(x,y)∈R×R:|x+y|≥3} and B={(x,y)∈R×R:|x|+|y|≤3}
From given figure, we get C = {(3, 0), (–3, 0), (0, 3), (0, –3)}
∑(x,y)∈C|x+y|=12