Let A, B, C be 3×3 matrices such that A is symmetric and B and C are skew-symmetric. Consider the statements:
(S1) A13B26-B26A13 is symmetric
(S2) A26C13-C13A26 is symmetric
Then, [2023]
(4)
Since A is symmetric. ∴A'=A
and B and C are skew symmetric.
∴B'=-B and C'=-C S1:(A13B26-B26A13)'=(A13B26)'-(B26A13)'
=(B')26(A')13-(A')13(B')26 (∵(X'Y')=(Y'X'))
=(-B)26(A)13-(A)13(-B)26
=B26A13-A13B26=-(A13B26-B26A13)
Which is skew symmetric.
∴S1 is false.
S2:(A26C13-C13A26)'=(A26C13)'-(C13A26)'
=(C')13(A')26-(A')26(C')13
=(-C')13A26-A26(-C)13=-C13A26+A26C13 Which is symmetric.
∴S2 is true.