Let a→ and b→ be two vectors such that |b→|=1 and |b→×a→|=2. Then |(b→×a→)–b→|2 is equal to [2024]
(1)
Given, |b→|=1 and |b→×a→|=2
Now, |(b→×a→)–b→|2=|b→×a→|2–2(b→×a→)·b→+|b→|2
=(2)2+1–2(0)=5.