Let a→ and b→ be two vectors. Let |a→|=1,|b→|=4 and a→·b→=2. If c→=(2a→×b→)-3b→, then the value of b→·c→ is [2023]
(2)
We have |a→|=1, |b→|=4, a→·b→=2
c→=(2a→×b→)-3b→
b→·c→=b→·((2a→×b→)-3b→)=b→·(2a→×b→)-3b→·b→
=0-3|b→|2=-3×(4)2=-3×16=-48