Let a and b be two positive integers such that a=p3q4 and b=p2q3, where p and q are prime numbers. If HCF(a,b)=pmqn and LCM(a,b)=prqs, then (m+n)(r+s)=
(3)
a=p3q4 and b=p2q3
HCF(a,b)=p2q3 ...(i)
and LCM(a,b)=p3q4 ...(ii)
But gives: HCF(a,b)=pmqn and LCM(a,b)=prqs
From eq. (i), pmqn=p2q3
So, m=2 and n=3
From eq. (ii), prqs=p3q4
So, r=3 and s=4
∴ (m+n)(r+s)=(2+3)(3+4)=35.