Let a1,a2,a3,..... be a GP of increasing positive numbers. If the product of fourth and sixth terms is 9 and the sum of fifth and seventh terms is 24, then a1a9+a2a4a9+a5+a7 is equal to________ . [2023]
(60)
Given, a4·a6=9
⇒(a5)2=9⇒a5=3 and a5+a7=24
⇒a5+a5r2=24⇒a5(1+r2)=24
⇒(1+r2)=8⇒r=7⇒a1=349
So, a1a9+a2a4a9+a5+a7=9+27+3+21=60