Let A = {1, 2, 3, 5, 8, 9}. Then the number of possible functions f:A→A such that f(m·n)=f(m)·f(n) for every m,n∈A with m·n∈A is equal to __________________ . [2023]
(432)
Let A={1,2,3,5,8,9}
f(m·n)=f(m)·f(n) for every m,n∈A and m·n∈A
Clearly, f(1)=1, i.e. f(3)=1or 3
Total functions = 1×6×2×6×6×1=432