Q.

Let a > 0. If the function f(x)=6x3–45ax2+108a2x+1 attains its local maximum and minimum values at the points x1 and x2 respectively such that x1x2=54, then a+x1+x2 is equal to :          [2025]

1 18  
2 24  
3 13  
4 15  

Ans.

(1)

We have, f(x)=6x3–45ax2+108a2x+1.

Since local max. and min. values occur when f'(x)=0

f'(x)=18x2–90ax+108a2=0 ⇒ x=2a and 3a

i.e., x1=2a, x2=3a 

Also, we have x1x2=54 ⇒ 6a2=54 ⇒ a=3

∴  a+x1+x2=3+6+9=18.