Let a > 0. If the function f(x)=6x3–45ax2+108a2x+1 attains its local maximum and minimum values at the points x1 and x2 respectively such that x1x2=54, then a+x1+x2 is equal to : [2025]
(1)
We have, f(x)=6x3–45ax2+108a2x+1.
Since local max. and min. values occur when f'(x)=0
f'(x)=18x2–90ax+108a2=0 ⇒ x=2a and 3a
i.e., x1=2a, x2=3a
Also, we have x1x2=54 ⇒ 6a2=54 ⇒ a=3
∴ a+x1+x2=3+6+9=18.