Q.

Let α>0, be the smallest number such that the expansion of (x23+2x3)30 has a term βx-α,βN. Then α is equal to ________ .               [2023]


Ans.

(2)

Here, Tr+1=Cr30(x2/3)30-r(2x3)r

=Cr30x(20-2r3-3r)(2)r=Cr30(2)rx(60-11r3); 0r30

For βx-α, α>0, r=6, and  T7=C630(2)6x-2α=2